For a titration of 25 ml of naoh solution, 23.30 ml of hcl solution if used. what is the molarity of naoh

Chemistry

1 answer:

Eduardwww [97]2 years ago

3 0

HCl(aq)+NaOH(aq)→NaCl(aq)+H2O(l)

As you can see here, one mole of acid neutralizes one mole of base.

We use the concentration equation, which states that,

c=nv

n is the number of moles v is the volume of solution

Rearranging for moles, we get,

n=c⋅v

So, we have:

nNaOH=0.1 M⋅0.05 L

=0.005 mol

Since one mole of acid neutralizes one mole of base, then we must have: nHCl=nNaOH.

And so,

cHCl=nHClvHCl

=0.005 mol0.03 L

≈0.17 M

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