A retail shop accepts only cash or checks suppose that 45% of its customers carry cash 44% carry checks and 31% carry both cash
and checks what is the probability that a randomly chosen customer at the top of the shop is carrying cash or checks are both
1 answer:
Answer:
Step-by-step explanation:
The number of customers carrying cash=45% = 0.45
The number of customers carrying checks= 44% =0.44
The number of customers carrying both = 31% = 0.31
So,
To find the probability we will write the expression:
cash+checks-cash or checks(both)=cash and checks
0.45+0.44-both=0.31
0.45+0.44-0.31=both
0.58=both....
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