Answer:
30
Step-by-step explanation:
if its asking for inches
Place the part (amount going to the left field), over the total amount of homerun:
(a) 2/57 is your probability
(b) Divide 2/57
2/57 = 0.035, or 3.5%
YES, it is unusual for this player to hit a home run to left field, for he only has a 3.5% chance.
hope this helps
Answer:
From what I know there is no q.
p=0 I put a slight explanation below.Hope it helps
Step-by-step explanation:
Ax^2+bx+c-p=x
Ax^2+bx+c-p-x=x-x
Ax^2+(b-1)x+c-p=0
Answer:
steps below
Step-by-step explanation:
3.2.1 AD = DB* sin 2 = DB * sin θ .. DE // AB ∠2= θ ... (1)
By laws of sines: DB / sin ∠5 = x / sin ∠4
∠4 = θ-α ∠5 = 180°-<u>∠1</u>-∠4 = 180°-<u>∠3</u>-∠4 = 180°-(90°-θ)-(θ-α)) = 90°+α
DB = (x*sin ∠5)/sin (θ-α)
= (x* sin (90°+α)) / sin (θ-α)
AD = DB*sinθ
= (x* sin (90°+α))*sinθ / sin (θ-α)
= x* (sin90°cosα+cos90°sinα)*sinθ / sin (θ-α) .... sin90°=1, cos90°=0
= x* cosα* sinθ / sin (θ-α)
3.2.2 Please apply Laws of sines to calculate the length