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2 years ago

What are the two main factors responsible for the formation of fossil fuel?

Physics

1 answer:

makvit [3.9K]2 years ago

5 0

Answer: Heat and pressure

Explanation:

I was taught that heat and pressure are the two main factors present when creating fossil fuel

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A uniform rod is set up so that it can rotate about a perpendicular axis at one of its ends. The length and mass of the rod are

igor_vitrenko [27]

Answer:

0.231 N

Explanation:

To get from rest to angular speed of 6.37 rad/s within 9.87s, the angular acceleration of the rod must be

$\alpha = \frac{\theta}{t} = \frac{6.37}{9.87} = 0.6454 rad/s^2$

If the rod is rotating about a perpendicular axis at one of its end, then it's momentum inertia must be:

$I = \frac{mL^2}{3} = \frac{1.27*0.847^2}{3} = 0.303kgm^2$

According to Newton 2nd law, the torque required to exert on this rod to achieve such angular acceleration is

$T = I\alpha = 0.303*0.6454 = 0.196 Nm$

So the force acting on the other end to generate this torque mush be:

$F = \frac{T}{L} = \frac{0.196}{0.847} = 0.231 N$

4 0

2 years ago

If the pressure of gas is doubled and its absolute temperature is quadrupled, the volume is what factor times the original?

Lapatulllka [165]

Answer:

Volume will increase by factor 2

So option (A) will be correct answer

Explanation:

Let initially the volume is V pressure is P and temperature is T

According to ideal gas equation $PV=nRT$ , here n is number of moles and R is gas constant

So $V=\frac{nRT}{P}$ ....................eqn 1

Now pressure is doubled and temperature is quadrupled

So new volume $V_{new}=\frac{nR4T}{2P}=\frac{2nRT}{P}$ ........eqn 2

Now comparing eqn 1 nad eqn 2

$V_{new}=2V$

So volume will increase by factor 2

So option (A) will be correct answer

8 0

2 years ago

At the normal boiling temperature of iron, TB = 3330 K, the rate of change of the vapor pressure of liquid iron with temperature

Margaret [11]

The molar latent enthalpy of boiling of iron at 3330 K is ΔH = 342 $\times$ 10^3 J.

<u>Explanation:</u>

Molar enthalpy of fusion is the amount of energy needed to change one mole of a substance from the solid phase to the liquid phase at constant temperature and pressure.

d ln p = (ΔH / RT^2) dt

(1/p) dp = (ΔH / RT^2) dt

dp / dt = p (ΔH / RT^2) = 3.72 $\times$ 10^-3

(p) (ΔH) / (8.31) (3330)^2 = 3.72 $\times$ 10^-3

ΔH = 342 $\times$ 10^3 J.

8 0

2 years ago

Read 2 more answers

Fermentation is a _________ process.

ivanzaharov [21]

Fermentation is an aerobic process which means it uses oxygen. anaerobic is a process with out oxegyn

4 0

2 years ago

A heat engine with 0.500 mol of a monatomic ideal gas initially fills a 1000 cm3 cylinder at 700 K . The gas goes through the fo

Zarrin [17]

Answer:

2234.63

Explanation:

Work done per cycle by the engine is calculated as;

$W=\int p \ dv$

#Since volume doesn't change in the isochoric steps, there is no work done, hence:

$W_2=W_3=0$

#For an isothermal change of state(ideal gas):

$pV=nRT\\\\W=P_iV_ i\int \frac{1}{V} \ dV\\\\=P_iV_ iIn(V_f/V_i)$

#for the expansion process:

$W_i=0.5mol\times8.3145J/molK\times 700K \ In(6000cm^3/1000cm^3)\\\\W_i=5214.15J$

$W_4=0.5mol\times8.3145J/molK\times 400K \ In(6000cm^3/1000cm^3)\\\\W_4=-2979.52$

$W=W_1+W_2+W_3+W_4\\\\=5214.15J-2979.52\\\\=2234.63J$

Hence, the engine does 2234.63J per second.

8 0

3 years ago