- - Let's solve for C.
Starting off with our equation:
Transform:
Solve for that:
Solve for that for the last time and your answer is
Length of outer boundary =30m
So area of outer boundary =30×30
= 900m²
Length of inner boundary of path=30-1= 29m
Inner area =29×29 =841m²
So area of path is= outer area - inner area
=900- 841
= 59m²
Only selections B and D give a maximum height of 13 at t=3. However, both of those functions have the height be -5 at t=0, meaning the ball was served from 5 ft below ground. This does not seem like an appropriate model.
We suspect ...
• the "correct" answers are probably B and D
• whoever wrote the problem wasn't paying attention.
perimeter =QR+RS+ST+TU+UQ =26.1
RQ = 5.39
RS = 4.47
ST = 3.61
TU = 4.12
UQ = 8.54
