Point A is the incenter of ΔDEF. What is the length of NA?
2 answers:
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Start with 3 one-by-one squares. This represents the '3' in 4t+3
Then draw 4 rectangles that are vertical or horizontal. Make sure the rectangle is longer than it is wide, or vice versa. The longer side is t units long (t is just a placeholder for a number). The shorter side is 1 unit long
The longer thin rectangles have an area of 1*t = t square units. Four of them represent t+t+t+t = 4*t = 4t
The small squares have an area of 1*1 = 1. Three of them represent 1+1+1 = 1*3 = 3
This is one possible way to draw it out. See the attached drawing.
Then draw 4 rectangles that are vertical or horizontal. Make sure the rectangle is longer than it is wide, or vice versa. The longer side is t units long (t is just a placeholder for a number). The shorter side is 1 unit long
The longer thin rectangles have an area of 1*t = t square units. Four of them represent t+t+t+t = 4*t = 4t
The small squares have an area of 1*1 = 1. Three of them represent 1+1+1 = 1*3 = 3
This is one possible way to draw it out. See the attached drawing.
Answer:
The equation of the line is 2 x - y + 5 = 0.
Step-by-step explanation:
Here the given points are A( 1, 7) & B( -3, - 1) -
Equation of a line whose points are given such that
( ) & (
)-
y - =
( x -
)
i.e. <em> y - 7= ( x- 1)</em>
<em> y - 7 = ( x -1)</em>
<em> y - 7 = 2 ( x - 1) </em>
<em> y - 7 = 2 x - 2</em>
<em> 2 x - y + 5 = 0</em>
Hence the equation of the required line whose passes trough the points ( 1, 7) & ( -3, -1) is 2 x - y + 5 = 0.