The domain is all possible x values.

In this case it goes from -2 to 6

So your domain is [-2,6] which is option b

Since the values -2 and 6 are included you use greater than or equal to and less than or equal to.

I

3 0

2 years ago

Solve the system : x = 2 - y and 3x + 3y = 6

Vesna [10]

Answer:

Option is d) Coincident lines.

Step-by-step explanation:

Given:

x = 2 - y and

3x + 3y = 6

Solution:

Let we rewrite the equations as

x + y = 2 ...................................Equation ( 1 )

3x + 3y = 6 ....................................Equation ( 2 )

Compare the above Two Equations with the following

a₁x + b₁y = c₁ and

a₂x + b₂y = c₂

We get

a₁ = 1 ; b₁ = 1 ; c₁ = 2 and

a₂ = 3 ; b₂ = 3 ; c₂ = 6

Now we will check

$\frac{a_{1}}{a_{2}}=\frac{1}{3}\\\\\frac{b_{1}}{b_{2}}=\frac{1}{3}\\\\\frac{c_{1}}{c_{2}}=\frac{2}{6}=\frac{1}{3} \\$

Now we get

$\frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}=\frac{1}{3}$

Which is the condition for a COINCIDENT LINES

COINCIDENT LINES have Infinite solutions for different x and different y

5 0

2 years ago

If 5/7 of x is 5/21 then what's x?

irinina [24]

$\frac{5}{7} \: \: \: of \: \: \: x = \frac{5}{21} \\ = > \frac{5x}{7} = \frac{5}{21} \\ = > 5x = \frac{5}{21} \times 7 \\ = > 5x = \frac{5}{3} \\ = > x = \frac{5}{3} \times \frac{1}{5} \\ = > x = \frac{1}{3}$

Answer:

$x = \frac{1}{3}$

Hope you could get an idea from here.

Doubt clarification - use comment section.

4 0

2 years ago