Question

A particle moves along a circular path over a horizontal xy coordinate system, at constant speed. At time t1 = 4.50 s, it is at point (5.80 m, 5.60 m) with velocity (3.50 m/s) j and acceleration in the positive x direction. At time t2 = 11.7 s, it has velocity (–3.50 m/s) i and acceleration in the positive y direction. What are the (a) x and (b) y coordinates of the center of the circular path? Assume at both times that the particle is on the same orbit.Expert Answer

Answer 1

Answer:

See it in the pic

Explanation:

See it in the pic