Let the width path be x.
Length of the outer rectangle = 26 + 2x.
Width of the outer rectangle = 8 +2x.
Combined Area = (2x + 26)*(2x + 8) = 1008
2x*(2x + 8) + 26*(2x + 8 ) = 1008
4x² + 16x + 52x + 208 = 1008
4x² + 68x + 208 - 1008 = 0
4x² + 68x - 800 = 0. Divide through by 4.
x² + 17x - 200 = 0 . This is a quadratic equation.
Multiply first and last coefficients: 1*-200 = -200
We look for two numbers that multiply to give -200, and add to give +17
Those two numbers are 25 and -8.
Check: 25*-8 = -200 25 + -8 = 17
We replace the middle term of +17x in the quadratic expression with 25x -8x
x² +17x - 200 = 0
x² + 25x - 8x - 200 = 0
x(x + 25) - 8(x + 25) = 0
(x+25)(x -8) = 0
x + 25 = 0 or x - 8 = 0
x = 0 -25 x = 0 + 8
x = -25 x = 8
The width of the path can not be negative.
The only valid solution is x = 8.
The width of the path is 8 meters.
One way is to factor and group and get every 3
729=3 times 3 times 3 times 3 times 3 times 3
so we group the ones that happen 3 times
729=(3*3*3) times (3*3*3)
we know that we can take the cube root of each group and multiply the result
729=
=(3)(3)=9
the answer is 9
Answer:
Step-by-step explanation:
What we know
total sum of angles = 540 deg
3/2 b cam also be written as 1.5b degrees.
So 1.5b + (b+45) + (2b - 90) +90 = 540
Step 1 -- get rid of parenthesis
1.5b + b + 45 +2b -90 +90 =540
Step 2 -- combine the like expressions
4.5b + 45 = 540
Step 3 -- subtract 45 from both the sides
4.5b = 495
Step 4 -- divide 4.5 from both the sides
b = 110 ----- not the right answer
Thats not right okay im sorry
but i guess if it is not 110 it should be 100, 90 etc.
90 = b is correct
Answer:-13
Step-by-step explanation:
-8 + b^2 - 5 - b^2
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-13
(0,8)+(7,-52) eso es la problema