Answer:
C. y= 6.18x + 10.9
Step-by-step explanation:
Every game that he plays (x) costs 6.18, for example, if he plays 3 games it would be 6.18 times 3 (games)
Now you have to add your admission, 10.9
To enter he needs to pay the admission ( 10.9 ) and also each game ( x ) he plays ( 6.18 )
Answer:
x = 12
Step-by-step explanation:
Solve for x:
(-3 x)/2 - 9 = -27
Put each term in (-3 x)/2 - 9 over the common denominator 2: (-3 x)/2 - 9 = (-18)/2 - (3 x)/2:
(-18)/2 - (3 x)/2 = -27
(-18)/2 - (3 x)/2 = (-3 x - 18)/2:
(-3 x - 18)/2 = -27
Multiply both sides of (-3 x - 18)/2 = -27 by 2:
(2 (-3 x - 18))/2 = -27×2
(2 (-3 x - 18))/2 = 2/2×(-3 x - 18) = -3 x - 18:
-3 x - 18 = -27×2
2 (-27) = -54:
-3 x - 18 = -54
Add 18 to both sides:
(18 - 18) - 3 x = 18 - 54
18 - 18 = 0:
-3 x = 18 - 54
18 - 54 = -36:
-3 x = -36
Divide both sides of -3 x = -36 by -3:
(-3 x)/(-3) = (-36)/(-3)
(-3)/(-3) = 1:
x = (-36)/(-3)
The gcd of -36 and -3 is -3, so (-36)/(-3) = (-3×12)/(-3×1) = (-3)/(-3)×12 = 12:
Answer: x = 12
Answer:
9.45z :)
Step-by-step explanation:
Answer:
hundredths
Step-by-step explanation:
To solve this problem, you have to know these two special factorizations:
Knowing these tells us that if we want to rationalize the numerator. we want to use the top equation to our advantage. Let:
![\sqrt[3]{x+h}=x\\ \sqrt[3]{x}=y](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%2Bh%7D%3Dx%5C%5C%20%5Csqrt%5B3%5D%7Bx%7D%3Dy%20)
That tells us that we have:
So, since we have one part of the special factorization, we need to multiply the top and the bottom by the other part, so:
So, we have:
![\frac{x+h-h}{h(\sqrt[3]{(x+h)^2}+\sqrt[3]{(x+h)(x)}+\sqrt[3]{x^2})}=\\ \frac{x}{\sqrt[3]{(x+h)^2}+\sqrt[3]{(x+h)(x)}+\sqrt[3]{x^2}}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%2Bh-h%7D%7Bh%28%5Csqrt%5B3%5D%7B%28x%2Bh%29%5E2%7D%2B%5Csqrt%5B3%5D%7B%28x%2Bh%29%28x%29%7D%2B%5Csqrt%5B3%5D%7Bx%5E2%7D%29%7D%3D%5C%5C%20%5Cfrac%7Bx%7D%7B%5Csqrt%5B3%5D%7B%28x%2Bh%29%5E2%7D%2B%5Csqrt%5B3%5D%7B%28x%2Bh%29%28x%29%7D%2B%5Csqrt%5B3%5D%7Bx%5E2%7D%7D%20)
That is our rational expression with a rationalized numerator.
Also, you could just mutiply by:
![\frac{1}{\sqrt[3]{x_h}-\sqrt[3]{x}} \text{ to get}\\ \frac{1}{h\sqrt[3]{x+h}-h\sqrt[3]{h}}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B%5Csqrt%5B3%5D%7Bx_h%7D-%5Csqrt%5B3%5D%7Bx%7D%7D%20%5Ctext%7B%20to%20get%7D%5C%5C%20%5Cfrac%7B1%7D%7Bh%5Csqrt%5B3%5D%7Bx%2Bh%7D-h%5Csqrt%5B3%5D%7Bh%7D%7D%20)
Either way, our expression is rationalized.
