The digit in the tens place is 1.
The digit in the tenths place is 0.
Answer:
12m
Step-by-step explanation
If the height of the ball after x seconds be modelled by the equation
h(x)=−(x−2)² +16
The height of the ball at the time it is thrown will be the height at the initial time. At that point that it is initially thrown the time is 0seconds i.e x = 0
To get the height at t x = 0seconds, we will substitute x = 0 into the modeled function to have;
h(0) = -(-0-2)²+16.
h(0) = -(-2)²+16
h(0) = -4+16
h(0) = 12
The height of the ball at the time the ball is thrown is 12m
9514 1404 393
Answer:
x = 22.5°
Step-by-step explanation:
Angle BED ≅ angle EBC = 6x, so angle BEA = 4x. The angles FEB and BEA form a linear pair, so we have ...
4x +4x = 180°
x = 22.5° . . . . . . divide by 8
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BED and EBC are "alternate interior angles" with respect to transversal BE crossing parallel lines DE and AC.
The mode's of this set of data are 1,2, and 4.
Answer:
so the vertex is (-4, 0) and the axis of symmetry is x=-4
Step-by-step explanation:
f(x) ≥ -(x+4)^2
f(x) ≥ -(x- -4)^2
this is in the form
f(x)> a(x-h)^2 +k
where (h,k) is the vertex and h is the axis of symmetry
so the vertex is (-4, 0) and the axis of symmetry is x=-4