Answer:
just add the equation and solve it then the value of X could be found then put the value of X and the value of y can be found. Just like in the below
Step-by-step explanation:
X+y=3 ------------ equation 1
4x-y=7 ------------ equation 2
adding equation 1 and 2
X+y=3
+ 4x-y=7
-----------------
5x = 10
X = 10/5
X = 2
putting the value of X in equation 1
or, 2+y=3
or, y = 3-2
Thus, y = 1
Answer:
1/1
Step-by-step explanation:
The reason why is because the spinner has 12 slices and on that spinner there is 12 yellow slices meaning all the slices on the spinner are yellow.
This means it is a 100% chance to land on yellow but 100% aas a fraction is 100/100.
You can simplify 100/100 a hundred times to 99/99 to 98/98 you can keep doing it but it's lowest form is the lowest number besides zero and that is 1 so it's lowest form is 1 out of 1 or 1/1 or 100%.
Hope this helps have a great afternoon:)
If you would like to solve <span>(8r^6s^3 – 9r^5s^4 + 3r^4s^5) – (2r^4s^5 – 5r^3s^6 – 4r^5s^4), you can do this using the following steps:
</span>(8r^6s^3 – 9r^5s^4 + 3r^4s^5) – (2r^4s^5 – 5r^3s^6 – 4r^5s^4) = 8r^6s^3 – 9r^5s^4 + 3r^4s^5 – 2r^4s^5 + 5r^3s^6 + 4r^5s^4 = 8r^6s^3 – 5r^5s^4 + r^4s^5<span> + 5r^3s^6
</span>
The correct result would be 8r^6s^3 – 5r^5s^4 + r^4s^5<span> + 5r^3s^6.</span>
Answer:
The value of Car B will become greater than the value of car A during the fifth year.
Step-by-step explanation:
Note: See the attached excel file for calculation of beginning and ending values of Cars A and B.
In the attached excel file, the following are used:
Annual Depreciation expense of Car A = Initial value of Car A * Depreciates rate of Car A = 30,000 * 20% = 6,000
Annual Depreciation expense of Car B from Year 1 to Year 6 = Initial value of Car B * Depreciates rate of Car B = 20,000 * 15% = 3,000
Annual Depreciation expense of Car B in Year 7 = Beginning value of Car B in Year 7 = 2,000
Conclusion
Since the 8,000 Beginning value of Car B in Year 5 is greater than the 6,000 Beginning value of Car A in Year 5, it therefore implies that the value Car B becomes greater than the value of car A during the fifth year.