(a) what are the x and y components of each vector?
For vector v1:
v1 = 6.6 (cos (180) i + sine (180) j)
v1 = 6.6 (-1i + 0j)
v1 = -6.6i
For vector v2:
v2 = 8.5 (cos (55) i + sine (55) j)
v2 = 8.5 ((0.573576436) i + (0.819152044) j)
v2 = 4.88 i + 6.96 j
(b) determine the sum v v 1 2
The sum of both vectors is given by:
v1 + v2 = (-6.6i) + (4.88 i + 6.96 j)
Adding component to component:
v1 + v2 = (-6.6 + 4.88) i + (6.96) j
v1 + v2 = (-1.72) i + (6.96) j
12 times ten equals one hundred twenty
1. 156
2. 15.6
3. 1.56
You just move the decimal point in depending on the number or zeros.
Answer:
see explanation
Step-by-step explanation:
The n th term of a geometric sequence is
= a₁
where a₁ is the first term and r the common ratio, hence
= 6 × = 6 × - = 6 × - = -