The intensity of a fire alarm that measures 125 dB loud is 268,337.29
<h3>Formula and expressions</h3>
Given the expression L=10 logI
where;
- L is the loudness
- I is the intensity of the sound.
Given the following parameters
L = 125dB
Substitute the given parameters into the following
L=10 logI
125 = 10logI
logI = 125/10
logI = 12.5
I = e^12.5
I = 268,337.29
Hence the intensity of a fire alarm that measures 125 dB loud is 268,337.29
Learn more on subject of formula here: brainly.com/question/657646
The markup is 8%, meaning it costs 8% more.
The starting price is 100%.
Therefore, the markup is 108% of $12.
If we multiply 12 by 108% (1.08), we will get our answer of $12.96
Answer: 34/25
Step-by-step explanation:
(136÷4)(100÷4) = 34/25 when reduced to the simplest form. As the numerator is greater than the denominator, we have an IMPROPER fraction,
Step 1 ) Move all terms right side of the equation.
Step 2 ) Apply quadratic formula. (Note: There are 2 solutions)
,
Step 3 ) Simplify.
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,
Since the options only provide one of the answer we found, the answer is...
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- <em>Marlon Nunez</em>
Answer:
I think it is b
Step-by-step explanation: