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2 years ago

15

Is it possible to have a relative atomic mass less then 24 or more than 26

1 answer:

qwelly [4]2 years ago

6 0

I think Magnesium not sure because the relative atomic mass of magnesium is 24,31.

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What affects the direction of the current moving through a wire? Check all that apply

NISA [10]

Answer : Option A) The direction the wire moves in

and Option C) the direction of the magnetic field.

Explanation : The direction of current flowing through the wire mainly depens on two factors which are i) direction of the wire moves in and ii) the direction of magnetic field.

The flow of current will occur in the direction of the wire through which it is moving in, whereas the direction of magnetic field will be in concentric circles around the direction of current passing through the wire.

6 0

2 years ago

The pH of an acid has nothing to do with the strength of the acid.

Levart [38]

Answer:

false

Explanation:

6 0

2 years ago

Explain why the electron configuration of 2-3-1 represents an atom in an excited state.

Allushta [10]

Answer:

The excited state electron configuration of an atom indicates the promotion of a valence electron to a higher energy state.

4 0

2 years ago

How many grams of KCl is needed to make .75 L of a 1 M solution of KCl?

Zielflug [23.3K]

Answer:

The answer to your question is 25.9 g of KCl

Explanation:

Data

Grams of KCl = ?

Volume = 0.75 l

Molarity = 1 M

Formula

$Molarity = \frac{number of moles}{volume}$

Solve for number of moles

$Number of moles = Molarity x volume$

Substitution

Number of moles = 1 x 0.75

Simplification

Number of moles = 0.75 moles

Molecular mass KCl = 39 + 35.5 = 34.5

Use proportions to find the grams of KCl

34.5 g of KCl ---------------- 1 mol

x ---------------- 0.75 moles

x = (0.75 x 34.5) / 1

x = 25.9 g of KCl

3 0

2 years ago

Consider the reaction below. HI + H2O mc014-1.jpg H3O+ + I– Which is an acid-conjugate base pair? HI and H2O H2O and H3O+ H3O+ a

lesya692 [45]

Answer: Option (d) is the correct answer.

Explanation:

According to Bronsted-Lowry, species which donate a proton are known as acid. The species which accept a proton are known as a base.

In the given reaction, acids and bases are as follows.

HI + $H_{2}O$ $\rightarrow$ $H_{3}O^{+}$ + $I^{-}$

Acid Base Conjugate acid Conjugate base

Therefore, the acid HI loses a proton to form a conjugate base that is $I^{-}$ .

Thus, we can conclude that HI and $I^{-}$ is an acid conjugate base pair.

4 0

2 years ago

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