The two triangles are congruent it two sides and the included angle of one triangle are respectively equal to two sides and angle of the other triangle
Because the square has similar lengths, the equation would be
(7x-2)(7x-2)
We can use FOIL to solve this:
The area is 49x^2 - 28x + 4 in^2.
Answer:
Jenny is wrong the correct answer is x²+ 4 - 4 x.
Step-by-step explanation:
Given that
(x-2)³∕x-2
(x-2)³∕(x-2) =(x-2) (x-2)²∕(x-2)
(x-2)³∕(x-2) = (x-2)²
As we know that
(a-b)² = a²+b² - 2 ab
So
(x-2)² = x²+ 2² - 2 ˣ 2 ˣ x = x²+ 4 - 4 x
(x-2)² = x²+ 4 - 4 x
It means that
(x-2)³∕(x-2) = (x-2)² = x²+ 4 - 4 x
So Jenny is wrong the correct answer is x²+ 4 - 4 x.
600 and 60 I do not know what to do