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2 years ago

Please some help me fast

Mathematics

1 answer:

alisha [4.7K]2 years ago

8 0

Answer:

Step-by-step explanation:

To find the best equation, we simply substitute the values of a, b, and c into the given equations.

a = 21

b = 5

c = 36

$a=\dfrac{7}{10}b\sqrt{c}$

$21=\dfrac{7}{10}5\sqrt{36}$

$21=\dfrac{7}{10}5(6)$

$21=\dfrac{7}{10}30$

$21=(0.7)30$

$21=21$

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Please help!

AfilCa [17]

Answer:

a.) P(HH|C)=2/5

Explanation:

Given following:

P(HH) = 7

P(C) = 10

P(HH ∩ C) = 4

P(HH ∪ C) = 13

Solving steps:

$\sf P(HH|C) = \dfrac{P(HH \cap C) }{P(C)}$

$\sf P(HH|C) = \dfrac{4 }{10}$

$\sf P(HH|C) = \dfrac{2 }{5}$

8 0

1 year ago

Last year, James earned £1,100 per month. This year, he's had a 4% increase in his monthly pay. He worked 40 hours per week for

avanturin [10]

Answer:

A = £7.15 per hour

James' average pay per hour this year is £7.15 per hour

Step-by-step explanation:

Given;

Last year pay = £1,100 per month

This year, he's had a 4% increase in his monthly pay

This year pay P = 1,100 + 4% of 1,100 = 1,100 +1,100(0.04)

This year pay P = £1,144 per month

Yearly pay Tp= 12 × P = 12 × £1,144 = £13,728

Number of hours worked this year;

He worked 40 hours per week for 48 weeks in the year

N = 40 hours per week × 48 weeks per year

N = 1920 hours per year

Average pay per hour this year A;

A = Yearly pay/Number of hours worked this year

A = Tp/N

A = £13,728/1920hours

A = £7.15 per hour

James' average pay per hour this year is £7.15 per hour

5 0

2 years ago

8 to 11 do it with equations thx

Alenkasestr [34]

Answer:

Step-by-step explanation:

8. $4\geq x+\frac{3}{4}$

$4(4\geq x+\frac{3}{4} )$

$16\geq 4x + 3$

$-3$ $-3$

$13\geq 4x$

$\frac{13}{4}\geq \frac{4x}{4}$

$\frac{13}{4} \geq x = x\leq \frac{13}{4}$

$x\leq \frac{13}{4}=3.25$

9. $x-3\leq -8$

$+3$ $+3$

$x\leq -5}$

10. $4\leq x-7$

$+7$ $+7$

$11\leq x=x\geq 11$

11. 6.9 < x - 2.3

+ 2.3 + 2.3

9.2 < x = x > 9.2

Hope this helps!

5 0

1 year ago

The height after t seconds of an object projected upward with an initial velocity of 48 feet per second from a 210-foot tower ca

svetlana [45]

Given:

The height h of an object after t seconds is

$h=-16t^2+48t+210$

The height of a neighboring 50-foot tall building is modeled by the equation h=50.

The time (t) when the object will be at the same height as the building is found to be t = –2 and t = 5.

To find:

The statement which describes the validity of these solutions.

Solution:

We have,

$h=-16t^2+48t+210$

Here, t is the time in seconds.

For t=-2,

$h=-16(2)^2+48(-2)+210$

$h=-64-96+210$

$h=50$

For t=5,

$h=-16(5)^2+48(5)+210$

$h=-400+240+210$

$h=50$

So, the value of h is 50 at t=-2 and t=5.

We know that time is always positive so it cannot be negative value. It means t=-2 is not possible.

The solution t = 5 is the only valid solution to this system since time cannot be negative.

Therefore, the correct option is C.

6 0

2 years ago

A sample of 50 impossible whoppersandwiches have a mean fat content of 37.6g and standard deviation of 4.9g . A sample of 58 reg

cluponka [151]

Answer:

Step-by-step explanation:

H0: Î¼1____ Î¼2For Q17(circle one: equal to, <u>less than or equal to</u>, greater than or equal to, not equal to )

H1 : Î¼1____ Î¼2For Q18(circle one: equal to, less than, <u>greater than</u>, not equal to )

Formula for calculating the the test:

t = [ (x₁ - x₂) - d ] / sqrt[(s₁²/n₁) + (s₂²/n₂)]

where x₁ = 37.6, x₂ = 39.3, d = 0 assuming equality = 37.6 - 39.3 = -1.7

s₁² = 4.92 = 24.01, s₂² = 2.72 = 7.29, n₁ = 50, n₂ = 58.

thus, t = [ (-1.7) - (0)] / √(24.01/50) + (7.29/58)

t = (-1.7) / (0.4802 + 0.1257)

t = -1.7 / 0.6059

t = -2.8057. = -2.81

P value:

Lets find the degree of freedom:

DF = (s₁²/n₁ + s₂²/n₂)² / { [ (s₁² / n₁)² / (n₁ - 1) ] + [ (s₂² / n₂)² / (n₂ - 1) ] }

DF = (24.01/50 + 7.29/58)² / {[(24.01 / 50)² / 50-1)] + (7.29/58)² / 58-1)]}

DF = (0.4802 + 0.1257)² /{[ (0.4802)²/49] + (0.1257)²/57)]}

DF = (0.6059)²/ (0.00471 + 0.00028)

DF = 0.3671 / 0.00499 = 75.37

Thus, P value = 0.9968 using a t distribution calculator.

Decision/Conclusion: Since the P value 0.9968 is greater than α (.05), Fail to Reject H0, There is not sufficient evidence to warrant the rejection of the claim.

4 0

2 years ago