Given ????(a1, aa2), ????(????1, ????2), ????(c1, c2), and ????(d1, d2), find a general formula in terms of a1, a2, ????1, ????2
1 answer:
You might be interested in
Answer:
The correct statement is:
C. Buying a needle and buying a thread are dependent events.
Explanation:
The first statement is incorrect because the given events are dependent on each other because the probability that a customer buys a needle given that the customer buys thread is 0.25.
The second statement is incorrect because we cannot say all those who buy a thread also buy a needle.
The fourth statement is incorrect because the probability that a customer buys a needle and thread is
1. It's all about pattern matching, as a lot of math is.
Letter A corresponds to letter J, as both are first in the names of their respective triangles.
Letter B corresponds to letter K, as both are second in the triangle names. Likewise, letter C corresponds to letter L, as both are last.
Realizing this, it should not be too much of a stretch to see
∠B ⇒ ∠K
∠C ⇒ ∠L
AC ⇒ JL
BC ⇒ KL
2. Same deal. Match the patterns. Here, you're counting rings in the angle marks.
1 ⇒ 1, so A ⇒ R
2 ⇒ 2, so B ⇒ Q
since the figures are reportedly similar, you can continue in the same order to finish.
ABCD ~ RQPS
3. The marked triangles cannot be similar. There are a number of ways to figure this. Basically, you want the ratios of sides to be the same for any similar triangles.
Here, you can eliminate the marked ones because the short side is too short relative to the others. (The average of the other two sides is double the short side in the similar triangles.)
Letter A corresponds to letter J, as both are first in the names of their respective triangles.
Letter B corresponds to letter K, as both are second in the triangle names. Likewise, letter C corresponds to letter L, as both are last.
Realizing this, it should not be too much of a stretch to see
∠B ⇒ ∠K
∠C ⇒ ∠L
AC ⇒ JL
BC ⇒ KL
2. Same deal. Match the patterns. Here, you're counting rings in the angle marks.
1 ⇒ 1, so A ⇒ R
2 ⇒ 2, so B ⇒ Q
since the figures are reportedly similar, you can continue in the same order to finish.
ABCD ~ RQPS
3. The marked triangles cannot be similar. There are a number of ways to figure this. Basically, you want the ratios of sides to be the same for any similar triangles.
Here, you can eliminate the marked ones because the short side is too short relative to the others. (The average of the other two sides is double the short side in the similar triangles.)