Answer:
v₂' = 19 m/s
Explanation:
given,
mass of car one = m₁ = 2000 Kg
mass of car two = m₂ = 1000 Kg
velocity of car one in right (v₁) = 10 m/s
velocity of car two in left (v₂)= 15 m/s
after collision
velocity(v₁') = 7 m/s
v₂' = ?
using conservation of momentum
m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'
m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'
2000 x 10 - 1000 x 15 = - 2000 x 7 + 1000 v₂'
1000 v₂' = 19000
v₂' = 19 m/s
Answer:
3.33m
Explanation:
Given parameters:
Force applied =500N
Elastic constant = 150N/m
Unknown:
Amount of stretch or extension = ?
Solution:
To solve this problem use the expression below:
F = k e
F is the force applied
k is the elastic constant
e is the extension
So;
500 = 150 x e
e = = 3.33m
d = distance traveled by her on her bicycle on a long flat road = 24 kilometer
t = time taken by her to travel distance "d" on her bicycle on a long flat road = 1.2 hours
v = average speed of vivian = ?
we know that average speed is given as
v = d/t
inserting the values in the above formula
v = 24 kilometer / 1.2 hour
v = 20 kilometer/hour
hence the correct choice is
C) 20 km/h
To calculate force, use the formula force equals mass times acceleration, or F = m × a. Make sure that the mass measurement you're using is in kilograms and the acceleration is in meters over seconds squared. When you've solved the equation, the force will be measured in Newtons.