When 2.00 kJ of energy is transferred as heat to nitrogen in a cylinder fitted with a piston with an external pressure of 2.00 a
1 answer:
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Balanced Half reactions are:
At anode 2 ==> Cl₂+
+ H₂O ==>
+ 2
+
At Cathode: 2 +
==> H₂
Since the question states that you are using an aqueous solution of MnCl₂, so ions will have present are, H₂O, ,
and
Now at Anode reaction will occur as given:
2 ==> Cl₂+
+ H₂O ==>
+ 2
+
(will occur)
At Cathode:
2 +
==> H₂ (will occur)
At Cathode:
+
==> Mn (This reaction will not occur)
The deposition of solid Mn will not occur because in aqueous solution, will be reduced before
.
The reduction potentials for is zero whereas reduction potential for
is - 1.18V.
The reduction potential of a species is its tendency to gain electrons and get reduced. It is measured in millivolts or volts. Larger positive values of reduction potential are indicative of a greater tendency to get reduced.
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