Answer:
Ammonia, 
Explanation:
If a Rac variant, in which the residue at position 61 was replaced with an alanine (Rac-61A), was synthesized. Also, Wild-type Rac and Rac-61A were incubated separately with VopC.
In order to obtain data to support that VopC modifies Rac at residue 61, the samples should be analyzed for the presence of Ammonia (![NH_{3}[\tex]) compound.In chemistry, the Vanadyl Phthalocyanine (VopC) comprises of a catalytic domain that activates host cells GTPase Rac irreversibly, through the deamide side chain of the residue existing at position 61.Also, we know that a deamidation reaction gives off Ammonia, [tex](NH_{3})](https://tex.z-dn.net/?f=NH_%7B3%7D%5B%5Ctex%5D%29%20compound.%3C%2Fp%3E%3Cp%3EIn%20chemistry%2C%20the%20Vanadyl%20Phthalocyanine%20%28VopC%29%20comprises%20of%20a%20catalytic%20domain%20that%20activates%20host%20cells%20GTPase%20Rac%20irreversibly%2C%20through%20the%20deamide%20side%20chain%20of%20the%20residue%20existing%20at%20position%2061.%3C%2Fp%3E%3Cp%3EAlso%2C%20we%20know%20that%20a%20deamidation%20reaction%20gives%20off%20Ammonia%2C%20%5Btex%5D%28NH_%7B3%7D%29)
and as such when ammonia is present in the sample containing Wild-type Rac but not in Rac-61A, this simply proves or provide the data to support that VopC modifies Rac at residue 61.
<em>Additionally, deamidation can be defined as the chemical conversion (hydrolysis) of an amide functional group such as glutamine, asparagine, in a polypeptide to another functional group such as glutamic acid or isoaspartic acid respectively by treating it with a strong acid (deamidate, transamidase). </em>
Answer:
The molecular magnets are arranged in an open chain so that the north pole or the south pole of the molecular magnets lie in the same direction which gives strong force at the poles whereas two opposite poles are arranged at the middle and the force cancel each other. So, poles have more force than the middle portion.
You would most likely be witnessing an eclipse
Answer:
) the uniform disk has a lower moment of inertia and arrives first.
Explanation:
(a) the uniform disk has a lower moment of inertia and arrives first.
(b) Let's say the disk has mass m and radius r, and
the hoop has mass M and radius R.
disk: initial E = PE = mgh
I = ½mr², so KE = ½mv² + ½Iω² = ½mv² + ½(½mr²)(v/r)² = (3/4)mv² = mgh
m cancels, leaving v² = 4gh / 3
hoop: initial E = Mgh
I = MR², so KE = ½MV² + ½(MR²)(V/R)² = MV² = Mgh
M cancels, leaving V² = gh
Vdisk = √(4gh/3) > Vhoop = √(gh)
Answer:
I'm gonna say it's D
Explanation:
but when u do the experiment on in u head you'll actually find out that it is actually , indeterminable
