Answer:
The statement is false. Exterior angles are the angles created when the sides of the triangle are extended
Step-by-step explanation:
In order to find the exterior angle of a polygon, the side of the polygon is extended to go past the vertex of the polygon to form an angle adjacent and supplementary to the the interior angle of the polygon at the vertex of the polygon where the exterior angle is formed.
The sum of the exterior angle and the adjacent interior angle is equal to 180°
The exterior angle can also be described as being formed by one side of a polygon and an extension of the adjacent side to previous side of the same polygon and it can also be referred to as a turning or an external angle.
To find the surface area of the rectangular prism the area of all the sides must be found and added together.
The formula for the surface area of a rectangular prism can be expressed as:
where
= length
= height
= width
Before plugging in the values in the equation the length of the prism must be converted to inches
1 ft. = 12 in.
Therefore 2 ft. = 24 in.
By plugging in the values of length, width, and height into the equation
2(24)(14) + 2(24)(11) + 2(14)(11) = 1508 in.²
Answer:
So, since there is an equal chance to roll any number on a six sided die, that means the chance of rolling any one number is one out of 6 or 1/6. You can see that with a diagram. Now, rolling two different numbers in a specific order you can tell with a diagram is 1/36.
Step-by-step explanation:
Y = -2x - 4
x + 4y = 19
x + 4(-2x - 4) = 19
x + (-8x) - 16 = 19
-7x - 16 = 19
-7x = 35
-x = 5
x = -5
y = -2x - 4
y = -2(-5) - 4
y = 10 -4
y = 6
Solution set {-5, 6} (C)
Answer:
a. 2.28%
b. 30.85%
c. 628.16
d. 474.67
Step-by-step explanation:
For a given value x, the related z-score is computed as z = (x-500)/100.
a. The z-score related to 700 is (700-500)/100 = 2, and P(Z > 2) = 0.0228 (2.28%)
b. The z-score related to 550 is (550-500)/100 = 0.5, and P(Z > 0.5) = 0.3085 (30.85%)
c. We are looking for a value b such that P(Z > b) = 0.1, i.e., b is the 90th quantile of the standard normal distribution, so, b = 1.281552. Therefore, P((X-500)/100 > 1.281552) = 0.1, equivalently P(X > 500 + 100(1.281552)) = 0.1 and the minimun SAT score needed to be in the highest 10% of the population is 628.1552
d. We are looking for a value c such that P(Z > c) = 0.6, i.e., c is the 40th quantile of the standard normal distribution, so, c = -0.2533471. Therefore, P((X-500)/100 > -0.2533471) = 0.6, equivalently P(X > 500 + 100(-0.2533471)), and the minimun SAT score needed to be accepted is 474.6653