I can't read that language but I'll guess it says write a second degree equation then solve for n when d=10.
Answer: n² - 3n - 20 = 0
That doesn't factor so there is no integer n solution.
That means there are no polygons with 10 diagonals.
f^-1(x) = sq.rt 5(x - 10)/5, sq.rt 5(x - 10)/5 is the inverse of y = 5x^2 +10
Step-by-step explanation:
interchanging the variables
x = 5y^2 + 10
5y^2 +10 = x
5y^2 = x - 10
dividing by 5
5y^2/5 = x/5 + -10/5
y^2 = x/5 + - 10/5
y^2 = x/5 - 2
y = 5 (x-10) 0/5 (sq.rt)
g(5x^2 + 10) = 5x/5
g(5x^2 + 10) = x
f^-1(x) = sq.rt 5(x - 10)/5, sq.rt 5(x - 10)/5 is the inverse of y = 5x^2 +10
Answer:
I might be wrong double check but it's something like
Step-by-step explanation:
4x/3-40/3
(not to sure on that so don't be mad if it's wrong)
Answer:
3 pounds
Step-by-step explanation:
12/4=3 (because we need to see how much bryant ate first)
12-3=9 (original - what bryant ate)
9/3=3 (what was left after bryant finish and what 1/3 of 9 is)
The answer is 1954. Letter C is correct
Solution:
If P(x) = <span>165,000
</span>Then
165,000 = 55,000(x - 1945<span>)^(1/2)
x= 1954
to check it, substitute x
</span>165,000 = 55,000(1954 - 1945)^(1/2)
165,000 =165,000
