The graph h = −16t^2 + 25t + 15 models the height and time of a ball that was thrown off of a building where h is the height in
feet and t is the time in seconds. At about what time did the ball reach the maximum height?
A) 0.80 seconds
B) 1 second
C) 2 seconds
D) 15 seconds
A) 0.80 seconds
B) 1 second
C) 2 seconds
D) 15 seconds
2 answers:
Answer:
Option A.
Step-by-step explanation:
The given function is
It models the height and time of a ball that was thrown off of a building where h is the height in feet and t is the time in seconds.
If a parabola is defined by function , then the vertex of the parabola is
In the given function a=-16, b=25 and c=15. It is a downward parabola and vertex of a downward parabola is point of maximum.
We need to find the time at which the height of ball is maximum. It means we need to find the x-coordinate of the vertex.
It means the ball reach the maximum height at about 0.80 seconds.
Therefore, the correct option is A.
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The formula of the Lateral Area of a cylinder is:
Lateral Area = 2
rh
=2(12)(60) (altitude is 5×radius)
(5×12=60)
=4523.9 mm² ≈ 4524 m²
Answer is D. 4524 m²
Lateral Area = 2
=2
(5×12=60)
=4523.9 mm² ≈ 4524 m²
Answer is D. 4524 m²