Hi!
There might be different variations into how anyone would approach this problem but this is by far an easy way for me.
In order to solve fractional relationships with a variable, a perfect way to solve them would be to cross multiply and make them equal to each other.
You see the part '3y+12', and when you criss cross over to the other side of the equation, you get three. Multiply that together.
When you see the part '6', when you glide diagonally, you find '4y'. Multiply this together as well. Make them equal to each other.
(<em>This is how you do cross multiplication.)</em>
You should get something like this:
3(3y+12)=6(4y) Distribute the three on the left side and multiply. Do the same on the right.
9y+36=24y Now, you can combine like terms by subtracting 9y to the other side.
36=15y Isolate y and divide it by 15.
y=2.4
I was unclear of the answer, so I plugged in 2.4 into the original equation where the y variable was, and got the right answer, so 2.4 should be the correct one no matter how you got it.
I hope this helped!
What is the decimal to this fraction
Answer:
http://www.youareanidiotreborn.org/
Step-by-step explanation:
7x² = 9 + x Subtract x from both sides
7x² - x = 9 Subtract 9 from both sides
7x² - x - 9 = 0 Use the Quadratic Formula
a = 7 , b = -1 , c = -9
x =
Plug in the a, b, and c values
x =
Cancel out the double negative
x =
Square -1
x =
Multiply 7 and -9
x =
Multiply -4 and -63
x =
Multiply 2 and 7
x =
Add 1 and 252
x =
Split up the
x =
The approximate square root of 253 is <span>15.905973.
</span>x ≈
Add and subtract
x ≈
Divide
x ≈
Round to the nearest hundredth
x ≈
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</span>
Answer:
(Some textbooks describe a proportional relationship by saying that " y varies proportionally with x " or that " y is directly proportional to x .") ... This means that as x increases, y increases and as x decreases, y decreases-and that the ratio between them always stays the same.
<h2>Hopefully u will satisfy with my answer..!!</h2><h2>Please Mark on brainleast please..!!</h2><h2>Have a nice day ahead dear..!!</h2>