Answer:
The 95% confidence interval for the true population mean of pollutant discharge is (26.7 tons, 33.7 tons).
Step-by-step explanation:
Let <em>X</em> represent the daily level of pollutant discharge in the manufacturing district in Pittsburgh.
The monitoring equipment reveals that for the 28 days of the February month
Mean daily discharge per factory, () = 30.2 tons
Standard deviation daily discharge per factory, (<em>s</em>) = 9.1 tons
Compute the critical value of <em>t</em> for 95% level of confidence and (n - 1 =) 27 degrees of freedom as follows:
*Use a t-table.
Compute the 95% confidence interval for the true population mean of pollutant discharge as follows:
Thus, the 95% confidence interval for the true population mean of pollutant discharge is (26.7 tons, 33.7 tons).
Answer:
7000 meters
Step-by-step explanation:
We know that 1 km = 1000 meters
7 km * 1000m/km = 7000 meters
150-25=125mph
130-25=105
This means it was going 125mph and that it dropped an altitude of 25 degrees because of the wind and the slow down of the helicopter
To do these, start by looking at the "b" value -6.
divide it by 2
-6/2 = -3
now square this number
(-3)^2 = 9
this is what you need for the "c" value
there is only a 5 for the c value so add 4 to both sides of the equation. ( +4 = +4)
y +4 = x^2 -6x +5 +4
y +4 = x^2 -6x +9
y +4 = (x -3)^2
y = (x -3)^2 - 4
vertex ( 3, -4) upwards facing like a bowl, because the "a" value is positive. So the vertex is the minimum, lowest point on the graph.
Answer: hiiiiiii lol
Step-by-step explanation: