Answer: One sample z test for means
Step-by-step explanation:
From the information given, the sample size is large. It is greater than 30. Again, the population standard deviation is given. This means that the test statistic would be the z score which is determined by the formula
z = (x - µ)/σ
Where
x = sample mean
µ = population mean
σ = population standard deviation
The probability value would be determined from the normal distribution table.
Therefore, the hypothesis test that should be used is
One sample z test for means
5<em>x</em>² - 7<em>x</em> + 2 = 0
5(<em>x</em>² - 7/5 <em>x</em>) + 2 = 0
5(<em>x</em>² - 7/5 <em>x</em> + 49/100 - 49/100) + 2 = 0
5(<em>x</em>² - 2 • 7/10 <em>x</em> + (7/10)²) - 49/20 + 2 = 0
5(<em>x</em> - 7/10)² - 9/20 = 0
5(<em>x</em> - 7/10)² = 9/20
(<em>x</em> - 7/10)² = 9/100
<em>x</em> - 7/10 = ± √(9/100)
<em>x</em> - 7/10 = ± 3/10
<em>x</em> = 7/10 ± 3/10
<em>x</em> = 10/10 = 1 or <em>x</em> = 4/10 = 2/5
All you have to do is add 399 to 10 and then multiply by ten. Then you get 199 and multiply by .08 and multiply that by ten. Then you subtract.
3
3(2x3+3x-4)
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