Answer:
A tree with a height of 6.2 ft is 3 standard deviations above the mean
Step-by-step explanation:
⇒ 
statement: A tree with a height of 5.4 ft is 1 standard deviation below the mean(FALSE)
an X value is found Z standard deviations from the mean mu if:
In this case we have: 
We have four different values of X and we must calculate the Z-score for each
For X =5.4\ ft
Therefore, A tree with a height of 5.4 ft is 1 standard deviation above the mean.
⇒
statement:A tree with a height of 4.6 ft is 1 standard deviation above the mean.
(FALSE)
For X =4.6 ft
Therefore, a tree with a height of 4.6 ft is 1 standard deviation below the mean
.
⇒
statement:A tree with a height of 5.8 ft is 2.5 standard deviations above the mean
(FALSE)
For X =5.8 ft
Therefore, a tree with a height of 5.8 ft is 2 standard deviation above the mean.
⇒
statement:A tree with a height of 6.2 ft is 3 standard deviations above the mean.
(TRUE)
For X =6.2\ ft
Therefore, a tree with a height of 6.2 ft is 3 standard deviations above the mean.
Explanation:
1. Identify the different constellations of variables. Here there are three:
2. Combine coefficients of each of the different variable constellations:
(8.1 -2.8)b +(6.7 +0.9)a +(2.5 +7)
5.3b +7.8a +9.5
3. Perform any other operations that might be required depending on the sort of equivalent wanted. For example, one could write ...
5.3(b +(78/53)a) +9.5 . . . . . . . shows the weight of a relative to b
answer is option D
because you can divide them like
so the option is D
please mark this answer as brainlist
Is it multiple choice or do you have to write a answer?
Answer:
The answer is 157
Step-by-step explanation:
