<u>Answer:</u> The final temperature of the solution is 
<u>Explanation:</u>
The amount of heat released by coffee will be absorbed by aluminium spoon.
Thus, 
To calculate the amount of heat released or absorbed, we use the equation:
Also,
![m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]](https://tex.z-dn.net/?f=m_1%5Ctimes%20c_1%5Ctimes%20%28T_%7Bfinal%7D-T_1%29%3D-%5Bm_2%5Ctimes%20c_2%5Ctimes%20%28T_%7Bfinal%7D-T_2%29%5D)
..........(1)
where,
q = heat absorbed or released
= mass of aluminium = 39 g
= mass of coffee = 166 g
= final temperature = ?
= temperature of aluminium = 
= temperature of coffee = 
= specific heat of aluminium = 
= specific heat of coffee= 
Putting all the values in equation 1, we get:
![39\times 0.904\times (T_{final}-24)=-[166\times 4.1801\times (T_{final}-83)]](https://tex.z-dn.net/?f=39%5Ctimes%200.904%5Ctimes%20%28T_%7Bfinal%7D-24%29%3D-%5B166%5Ctimes%204.1801%5Ctimes%20%28T_%7Bfinal%7D-83%29%5D)
Hence, the final temperature of the solution is
1) D: enormous
2) D: gravity
Answer:
2805 °C
Explanation:
If the gas in the tank behaves as ideal gas at the start and end of the process. We can use the following equation:
The key issue is identify the quantities (P,T, V, n) in the initial and final state, particularly the quantities that change.
In the initial situation the gas have an initial volume 
, temperature 
, and pressure 
,.
And in the final situation the gas have different volume 
and temeperature 
, the same pressure ,, and the same number of moles 
,.
We can write the gas ideal equation for each state:
and 
, as the pressure are equals in both states we can write
solving for
(*)
We know = 935 °C, and that the (the complete volume of the tank) is the initial volume plus the part initially without gas which has a volume twice the size of the initial volume (read in the statement: the other side has a volume twice the size of the part containing the gas). So the final volume 
Replacing in (*)
Answer: High voltage transmission minimizes energy losses during electricity transmission.
Explanation:
When electricity is to be transmitted over a long distance, high voltage transmission is preferred to minimize energy losses due to heat.
The higher the transmission voltage, the lower the current and the lesser the resitance in the wire and the lesser the energy lost due to heat during transmission.
High voltage transmission in kilowatts enables light weight cables to be used for long distance electricity transmission.
This explains why, even though only 110 V may be required at home by some appliances, but electricity is transmitted in kilovolts and often require a stepdown transformer
2nd stone time = 13.0/9.8 = 1.33 seconds
distance = 0.5*9.8*1.33^2 = 8.67 meters
1st stone time = 1.33+1.5 = 2.83 seconds
distance = 0.5*9.8*2.83^2 = 39.24 meters
39.24-8.67 = 30.57 meters apart
