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2 years ago

Find the real solutions of the equation by graphing

Mathematics

1 answer:

Vlada [557]2 years ago

8 0

Answer:

C. 0, 1.29, -0.65

Step-by-step explanation:

The real solutions of the equation $19x^3-12x^2-16x=0$ is where the graph of $y=19x^3-12x^2-16x$ intersects the x-axis.

This means that we need to graph $y=19x^3-12x^2-16x$ using a graphing software.

From the graph shown in the attachment $x=0$ , $x=1.29$ , and $x=-0.65$ are the real solutions.

The correct choice is C

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2 years ago

what is the equation in slope intercept form of the line that passes through the point (-4,47) and (2,-16)

Vilka [71]

The slope-intercept form:

$y=mx+b$

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Therefore we have:

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2 years ago

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Leno4ka [110]

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1 year ago

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2 years ago

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Tpy6a [65]

Answer:

infinitely many

Step-by-step explanation:

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Combine like terms

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Subtract 12x from each side

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2 years ago

Read 2 more answers