Give the expected organic product when 3-phenylpropanoic, PhCH2CH2COOH , is treated with NaOH, H20 .If more than one product is
possible, only draw the major product.Include counter-ions, e.g., Na+, I-, in your submission, but draw them in their own separate sketcher.Separate structures with + signs from the dropdown menu.
1 answer:
Answer:
when 3-phenylpropanoic, PhCH₂CH₂COOH , is treated with NaOH, H₂0 it produce sodium salt of 3 - phenylpropanoic acid with water as a major product.
Explanation:
Carboxylic acid when treated with a base like NaOH or KOH gives carboxylate ion because H⁺ from acid reacts with OH⁻ from base gives H₂0 and salt of sodium carboxylate.
The mechanism of the above reaction given below
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The balanced equation is attached in the image below. The coefficients are 2, 2, blank.
