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2 years ago

If a < b where on the line will a appear

Mathematics

1 answer:

kow [346]2 years ago

8 0

Less than were the b is.

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How do i find the unknown side length of #9?

Natali5045456 [20]

You can find the unknown side length by using pythagorean theorem. a²+b²=c²
Simply plug-in numbers into the formula. Your answer is 80.

4 0

2 years ago

Keri is making a doll clothes for a holiday craft show. The wholesale cost of the materials for one outfit is $9.38. If she sell

irinina [24]

Answer:

60%

Step-by-step explanation:

If I get you right, you're asking for the percentage gain to the nearest percentage, right?

Now to do this, we need to get the amount of profit she made. That's quite easy, we only need to subtract the cost price from the selling price. And that equals $15 - $9.38 that equals $5.62.

Now, we divide this value by the cost price and multiply by 100% to get the percentage gain.

I.e 5.62/9.38 × 100%.

That gives 59.9% , which equals 60% when approximated to the nearest percentage.

5 0

2 years ago

Help!!!!!!!<br> I need to find the surface area of this image.

Kaylis [27]

Answer:

length;12cm

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

A shirt originally cost $39.38, but it is on sale for $31.50. What is the percentage decrease of the price of the shirt? If nece

seraphim [82]

Answer:

20%

Step-by-step explanation:

1. subtract the new price from the original price

$39.38-31.50=7.88$

2. divide the difference by the original number

$7.88$ ÷ $39.38$ $=.2001$

3. multiply this number by 100

$(.2001)100=20%$

5 0

3 years ago

Which choice is equivalent to the expression below when y2 0?<br> √y^2 + √16y^3 – 4y√y

DanielleElmas [232]

Answer:

Option C.

Step-by-step explanation:

We start with the expression:

$\sqrt{y^3} + \sqrt{16*y^3} - 4*y\sqrt{y}$

where y > 0. (this allow us to have y inside a square root, so we don't mess with complex numbers)

We want to find the equivalent expression to this one.

Here, we can do the next two simplifications:

$\sqrt{16*y^3} = \sqrt{16} \sqrt{y^3} = 4*\sqrt{y^3}$

And:

$y*\sqrt{y} = \sqrt{y^2} *\sqrt{y} = \sqrt{y^2*y} = \sqrt{y^3}$

If we apply these two to our initial expression, we can rewrite it as:

$\sqrt{y^3} + \sqrt{16*y^3} - 4*y\sqrt{y}$

$\sqrt{y^3} + 4*\sqrt{y^3} - 4\sqrt{y^3} = \sqrt{y^3}$

Here we can use the second simplification again, to rewrite:

$\sqrt{y^3} = y*\sqrt{y}$

So, concluding, we have:

$\sqrt{y^3} + \sqrt{16*y^3} - 4*y\sqrt{y} = y*\sqrt{y}$

Then the correct option is C.

8 0

2 years ago