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2 years ago

If f(x) = -x^2 – 1, and g(x) = x + 5, then g(f (x)) = [? ]x^2+[ ]x + [ ]

Mathematics

1 answer:

inna [77]2 years ago

3 0

Answer:

g(f(x)) = - x² + 4

Step-by-step explanation:

To evaluate g(f(x)), substitute x = f(x) into g(x), that is

g(f(x))

= g(- x² - 1)

= - x² - 1 + 5

= - x² + 4

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Felix's washing machine uses 6 gallons of water. How much water does it use in liters? A gallon is approximately 3.79 liters. Ro

dlinn [17]

Answer:

22.74 liters

Step-by-step explanation:

GIven data

Felix's washing machine uses 6 gallons of water

we are told that A gallon is approximately 3.79 liters

Hence if a gallon is approximately 3.79 liters

then 6 gallons of water will be x liters

cross multiply we have

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2 years ago

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gulaghasi [49]

Answer:

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2 years ago

Four plumbers estimated the length of the radius of a cylindrical pipe. The estimates made by

o-na [289]

Answer:

B. $\frac{\sqrt{3}}{11}, \frac{\pi}{24}, \frac{3}{25}, \frac{9}{100}$

Step-by-step explanation:

The question is not properly presented. See attachment for proper presentation of question

From the attachment, we have that:

$W = \frac{3}{25}$

$X = \frac{\sqrt{3}}{11}$

$Y = \frac{9}{100}$

$Z = \frac{\pi}{24}$

Required

Order from greatest to least

First, we need to simplify each of the given expression (in decimals)

$W = \frac{3}{25}$

$W = 0.12$

$X = \frac{\sqrt{3}}{11}$

Take square root of 3

$X = \frac{1.73205080757}{11}$

$X = 0.15745916432$

$X = 0.16$ --- approximated

$Y = \frac{9}{100}$

$Y = 0.09$

$Z = \frac{\pi}{24}$

Take π as 3.14

$Z = \frac{3.14}{24}$

$Z = 0.13083333333$

$Z = 0.13$ --- approximated

List out the results, we have:

$W = 0.12$ $X = 0.16$ $Y = 0.09$ $Z = 0.13$

Order from greatest to least, we have:

$X = 0.16$ $Z = 0.13$ $W = 0.12$ $Y = 0.09$

Hence, the order of arrangement is:

$X = \frac{\sqrt{3}}{11}$ $Z = \frac{\pi}{24}$ $W = \frac{3}{25}$ $Y = \frac{9}{100}$

i.e.

$\frac{\sqrt{3}}{11}, \frac{\pi}{24}, \frac{3}{25}, \frac{9}{100}$

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Round off - 126,945 to the nearest hundred thousand nearest ten thousand nearest thousand which of these rounds amount to the cl

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