4.90× 10^2 L
I am guessing that the mass of the air is 6.32 × 10^2 <em>g</em>. Then,
Volume = 6.32 × 10^2 g × (1 L/1.29 g) = 4.90× 10^2 L
Answer:
There are
Explanation:
In this problem, we need to find the number of molecules in mol of .
The molar mass of is
No of moles = mass/molar mass
We can find mass from above formula.
Also,
No of moles = no of molecules/Avogadro number
Hence, there are
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Answer: 0.745 g of will be produced from 1.08 g of sodium sulfate
Explanation:
To calculate the moles :
is the limiting reagent as it limits the formation of product and is the excess reagent.
According to stoichiometry :
3 moles of produce = 3 moles of
Thus 0.0076 moles of will require= of
Mass of
Thus 0.745 g of will be produced from 1.08 g of sodium sulfate