Answer:
The velocity of the car after the collision is -5.36 m/s
Step-by-step explanation:
An elastic collision is an encounter between two bodies in which the total kinetic energy of the two bodies remains the same.
let the following:
m₁ = mass of the car = 1400 kg
m₂ = mass of the truck = 3200 kg
u₁ = velocity of the car before collision = 13.7 m/s
u₂ = velocity of the truck before collision = 0 m/s
v₁ = velocity of the car after collision
v₂ = velocity of the truck after collision
v₁ = [ u₁ * (m₁ - m₂) + u₂ * 2m₂ ]/ (m₁ + m₂)
= [ 13.7 * (1400 - 3200) + 0 * 2 * 3200 ]/ (1400 + 3200)
= - 5.36 m/s
So, <u>the velocity of the car after the collision is -5.36 m/s</u>
Answer:
u would have 3 cups of sugar
Step-by-step explanation:
Answer:
8763
Step-by-step explanation:
Let x represent the number of students the college had last year. Then this year's enrollment is ...
... x - 3%·x = 8500
... x(1 - 0.03) = 8500 . . . . . collect terms
... x = 8500/0.97 ≈ 8762.89 . . . . divide by the coefficient of x
Enrollment last year was about 8763.
_____
Of course, you know 3% = 3/100 = 0.03.
300m because area is Length x width and it's 3x as big as 10 meters it's 30 x 10= 300
