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2 years ago

If a sprinkler waters 1 over 8 of a lawn in 1 over 2 hours, how much time will it take to water the entire lawn?

Mathematics

2 answers:

timama [110]2 years ago

8 0

Answer:

4 hours

Step-by-step explanation:

it takes thirty minutes to water 1/8 of a lawn, so you will water 2/8 every hour. 8 divided by 2 is 4.

exis [7]2 years ago

5 0

Answer: 4 :)

Explain:I have no idea

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Allisa [31]

Answer:

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2 years ago

Find the remainder when 4 3 − 3 2 + 2 − 4 is divided by + 2

USPshnik [31]

Answer:

4.5

Step-by-step explanation:

43-32+2-4= 9

9/2= 4.5

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2 years ago

When Colton commutes to work, the amount of time it takes him to arrive is normally distributed with a mean of 41 minutes and a

N76 [4]

Answer:

(34, 48)

Step-by-step explanation:

According to the Empirical Rule, 95% of normally distributed data lie within two standard deviations of the mean. That, in turn, means 95% of the data in this problem lie within 2(3.5 min), or 7 min, of the mean:

41 - 7 < mean < 41 + 7, or

34 < mean < 48, or simply (34, 48)

6 0

2 years ago

What is 6/2(1+2)=?

Rufina [12.5K]

Answer:

Answer is 9

Step-by-step explanation:

Remember PEMDAS???

"parenthesis, exponents, multiplication, division, addition, subtraction"

you would first solve the addition inside of the parentheses (1 + 2 = 3), and from there finish the equation as it's written from left to right.

8 0

2 years ago

Read 2 more answers

At 3pm, the length of the shadow of a thin vertical pole standing on level ground is the same as the height of the pole. A while

aliya0001 [1]

Answer: The height of the pole is 175.97 ( approx )

Step-by-step explanation:

Let the height of the pole is x cm,

Also, let the angle of elevation of the sun to the pole at 3 pm is $\theta$

Thus, by the question,

$tan\theta = \frac{\text{ The height of the pole}}{\text{ The height of the shadow}}$

$\implies tan\theta = \frac{x}{x}$ ( at 3pm the height of shadow = height of the pole)

$\implies tan\theta = 1$

$\implies \theta = 45^{\circ}$

Again, according to the question,

When the angle of elevation is $(\theta - 12^{\circ})$ ,

The height of shadow = x + 95,

$\implies tan(45-12)^{\circ}=\frac{x}{x+95}$

$\implies tan 33^{\circ}=\frac{x}{x+95}$

$\implies tan 33^{\circ}x + 95\times tan33^{\circ}=x$

$\implies tan 33^{\circ}x - x = - 95\times tan33^{\circ}$

$\implies -0.3505924068 x = - 61.6937213538$

$x=175.969930202\approx 175.97\text{ cm}$

4 0

2 years ago