You would use distribution. So, in this case, it would be 10a - 50. You use -10 to multiply -a and 5, and you get 10a, and -50.
1
7.3
x 9.6
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438
+ 647 0
69. 0 8, hope that helped
Answer:
How many drinks should be sold to get a maximal profit? 468
Sales of the first one = 345 cups
Sales of the second one = 123 cups
Step-by-step explanation:
maximize 1.2F + 0.7S
where:
F = first type of drink
S = second type of drink
constraints:
sugar ⇒ 3F + 10S ≤ 3000
juice ⇒ 9F + 4S ≤ 3600
coffee ⇒ 4F + 5S ≤ 2000
using solver the maximum profit is $500.10
and the optimal solution is 345F + 123S
The pictures is black and theres only 15 and a 1 so im gonna guess 15
Step-by-step explanation:
sin(x) = M, M > 0
= sin(x - π)
= sin(x)cos(π) - cos(x)sin(π)
= sin(x).(-1) - cos(x).0
= -sin(x) - 0
= -sin(x)
= -M
