Answer:
The value of Y is 24 km and distance from A to C to B is AC+Y=18+24=42 km
Step-by-step explanation:
Given that A highway between points A and B has been closed for repairs. An alternative route between there two locations is to travel between A and C and then from C to B. we have to find the value of Y and the total distance from A to C to B. Let AB=Z
In ΔBCD and ΔABD
∠BCD=∠ABD (∵each 90°)
∠D=∠D (∵common)
By AA similarity, ΔBCD~ΔABD
∴ their corresponding sides are proportional
Comparing last two terms, we get
⇒
⇒
⇒
⇒
⇒
Hence, the roots are X=32, -50
X=-50 not possible as distance can never negative.
Hence, X=32 km
By applying Pythagoras theorem in ΔBCD we get
⇒
⇒
Hence, the value of Y is 24 km and the distance from A to C to B is AC+Y=18+24=42 km
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Answer:
-231/40
Step-by-step explanation:
The answer will be 158.50
5n +10(3n) +25(2n) = 340 . . . . will solve the problem
This simplifies to
5n +30n +50n = 340