A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).
<h3>Calculate the vertices of ΔA'B'C':</h3>
Given that,
ΔABC : A(-6,-7), B(-3,-10), C(-5,2)
(x,y)→(x,y-3)
The vertices are:
- A(-6,-7 )⇒ (-6,-7-3) = A'(-6, -10)
- B(-3,-10) ⇒ (-3,-10-3) = B'(-3,-13)
- C(-5,2) ⇒ (-5,2-3) = C'(-5,-1)
Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).
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Answer:
Tyler didn't make a mistake
Step-by-step explanation:
3(x+4)=-18
(x+4)=-18/3 (divide by 3 on both the sides)
x+4=-6
x=-6-4 (subtract 4 from both the sides)
x=-10
Answer:
8x + 12
Step-by-step explanation:
3(x + 4) + 5x
3x + 12 + 5x
8x + 12
Answer:
a) P=0.2503
b) P=0.2759
c) P=0.3874
d) P=0.2051
Step-by-step explanation:
We have this information:
25% of American households have only dogs (one or more dogs)
15% of American households have only cats (one or more cats)
10% of American households have dogs and cats (one or more of each)
50% of American households do not have any dogs or cats.
The sample is n=10
a) Probability that exactly 3 have only dogs (p=0.25)
b) Probability that exactly 2 has only cats (p=0.15)
c) Probability that exactly 1 has cats and dogs (p=0.1)
d) Probability that exactly 4 has neither cats or dogs (p=0.5)