The left end of a rod of length and rotational inertia is attached to a frictionless horizontal surface by a frictionless pivot,
as shown above. Point C marks the center (midpoint) of the rod. The rod is initially motionless but is free to rotate around the pivot. A student will slide a disk of mass toward the rod with velocity 0 perpendicular to the rod, and the disk will stick to the rod a distance x from the pivot. The student wants the rod-disk system to end up with as much angular speed as possible
1 answer:
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Answer:
7.468 kN
Explanation:
Here the force of 7468 Newton is given.
Some of the prefixes of the SI units are
kilo = 10³
Mega = 10⁶
Giga = 10⁹
The number is 7468.0
Here, the only solution where the number of significant figures is kilo
1 kilonewton = 1000 Newton
So 7468 N = 7.468 kN