What is the probability of choosing a number 1 - 10 that is greater than 5 or even?
1 answer:
Answer:
70%
Step-by-step explanation:
So, first, our set of choices is 10. This means that there are 10 choices.
We want a number that is greater than 5 or even. Thus, let's mark down all of our choices.
Numbers greater than 5 are:
6, 7, 8, 9, and 10.
Even numbers are:
2, 4, 6, 8, 10.
However, we already counted 6, 8, and 10 previously, so we'll ignore that.
All in all, the following numbers will satisfy our requirements:
2, 4, 6, 7, 8, 9, and 10.
This is 7 out of 10 numbers.
Therefore, our probability is:
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Answer:
x =
Step-by-step explanation:
x^2 + 8^2 = 9
Simplify the 8^2
x^2 + 64 = 9
Subtract 64 from both sides
x^2 = -55
Take the square root from both sides
x = +/-
Simplify
x =
Hope this helps!
Answer:
t = 3.69 ≈ 3. 7 years
Step-by-step explanation:
Given :
P = 10,000
r = 5%= 0.05
A = 12,000
n = 2 ( because it is compounded semi - annually )