Answer:
Let the to consecutive odd integers be 2n-1 and 2n+1
their average is
=>
=
= 
The square of the average is 
= 
One less than the square of their average = 
-----------------------------(1)
Now the product of the two consecutive odd numbers
(2n-1)( 2n+1) =
= 
------------------------------------(2)
From (1) and (2) ,
We can say that the product of two consecutive odd integers is always one less than the square of their average is true
For consecutive even integers
The product of two consecutive integers
(2n)(2n+2) = 
----------------------------(3)
Whereas, the one less than the square of their average is
= 
= 
=
= 2n--------------------------------------------(4)
From (3) and (4) it is clear that product of two consecutive even integers is not one less than the square of their average.
For this case we must solve the following equation:
To solve we follow the steps below:
We square both sides of the equation squared:
We choose the positive value because we talk about $. 
Answer:
$6
Answer:
Step-by-step explanation:
She writes 180words in 5min
In 1 min she writes = 180/5 words
= 36 words
In 1hr = 60min she will write = 36×60words
= 2160words
: she will write 2160words in 1hr
Answer:
Judah's hourly wage is $7/hr.
Step-by-step explanation:
x = (86 + 12)/14
x = 98/14
x = 7
Answer:
<em>The age of the oldest child id 7.</em>
Step-by-step explanation:
There are 5 children:
1st Child: 7 Years Old
2nd Child: 6 Years Old
3rd Child: 5 Years Old
4th Child: 4 Years Old
5th Child: 3 Years Old
<em>The ges of any two consecutive children difference is 2 years old: 1st Child and 3rd Child. </em>
Hope this helped! :-)
