This question has extraneous info to trick you.
f(x) = g(x)h(x) ⇒ f'(x) = g'(x)h'(x) . Letting x = 10, we get f'(10) = g'(10)h'(10). then just plug in the values provided. g(10) and h(10) are there to throw you off, just use g'(10) and h'(10).
So f'(10), pronounced "eff prime of ten", = 0 * 35 = 0.
If the question were asking for f(10) instead of f'(10) then you would use g(10) and h(10), ⇒-4*560=90.
Use the equation and type the ordered-pairs. y = log 3 x {(1/3, a0), (1, a1), (3, a2), (9, a3), (27, a4), (81, a5)
vagabundo [1.1K]
Answer:
Considering the given equation
And the ordered pairs in the format
I don't know if it is log of base 3 or 10, but I will assume it is 3.
For
So the ordered pair will be
For
So the ordered pair will be
For
So the ordered pair will be
For
So the ordered pair will be
For
So the ordered pair will be
For
So the ordered pair will be
3x +2= 5x
-3x
2= 2x
/2
1= x
So first I got all the x’s on one side and the whole numbers on the other side. So we had 2 on one side and 2x on the other. From there we divided by the number of x’s which was 2 so we can get one x only. So 2/2= 1 so x =1
Answer:
- 4 1/6 min or 4 min 10 sec
Step-by-step explanation:
<u>Filling rate is:</u>
- 15 ÷ 1 1/4 = 15 ÷ 5/4 = 15 × 4/5 = 12 l/min
<u>Total volume is 50 l, time required to fill is:</u>
- 50/12 = 4 2/12 = 4 1/6 min or 4 min 10 sec
Answer:
2^5
Step-by-step explanation:
1^10 = 1 (1*1*1*1*1....)
5^2 = 25 (5*5)
2^5 = 32 (2*2*2*2*2)
3^3 = 27 (3*3*3)