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2 years ago

How can you decide if finding common multiples and common factors is helpful in solving a problem? Explain.

1 answer:

6 0

<span>Have made a model (diagram, physical model, or numerical model) of the problem which helps me to visualize the details of the problem

Have answered the question, what do the factors of the numbers in this problem tell me about the situation?

Have answered the question, what do the multiples of the numbers in this problem tell me about the situation?

Have answered the questions, will breaking the numbers into facotrs help me solve this problem? If so, how?
<span>
Have answered the questions, will listing the multiples of the numbers in this problem help me to solve this problem? If so, how?</span></span>

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nora is planning a birthday party for her little sister, colleen. she needs to purchase 12 cupcakes she can not spend more than

Lapatulllka [165]

Answer:

if she cannot spend more than $40, she will spend .3 on each cupcake

Step-by-step explanation:

when you divide 12 by 40, you get .3 and to check if it is true, you can multiply .3 x 40 and you will get 12 hope you get it right, and have a good day :)

6 0

2 years ago

What are the coordinates of pont P on the coordinate grid below?

Shalnov [3]

Answer:

It would be (-5,3). Hope this helps!

Step-by-step explanation:

Start from zero on the x line and count until you get to the where the P is, then start from zero and count on the Y line till you get to the P.

5 0

2 years ago

Write the equation for the hyperbola with foci (–12, 6), (6, 6) and vertices (–10, 6), (4, 6).

fomenos

Answer:

$\frac{(x--3)^2}{49} -\frac{(y-6)^2}{32}=1$

Step-by-step explanation:

The standard equation of a horizontal hyperbola with center (h,k) is

$\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1$

The given hyperbola has vertices at (–10, 6) and (4, 6).

The length of its major axis is $2a=|4--10|$ .

$\implies 2a=|14|$

$\implies 2a=14$

$\implies a=7$

The center is the midpoint of the vertices (–10, 6) and (4, 6).

The center is $(\frac{-10+4}{2},\frac{6+6}{2}=(-3,6)$

We need to use the relation $a^2+b^2=c^2$ to find $b^2$ .

The c-value is the distance from the center (-3,6) to one of the foci (6,6)

$c=|6--3|=9$

$\implies 7^2+b^2=9^2$

$\implies b^2=9^2-7^2$

$\implies b^2=81-49$

$\implies b^2=32$

We substitute these values into the standard equation of the hyperbola to obtain:

$\frac{(x--3)^2}{7^2} - \frac{(y-6)^2}{32}=1$

$\frac{(x+3)^2}{49} -\frac{(y-6)^2}{32}=1$

7 0

2 years ago

Arithmetic and geometric

NISA [10]

I don’t understand the question

7 0

2 years ago

Please help me with the answer I keep getting it wrong

Vsevolod [243]

First because it's a broken line we know it's an inequality.

next we find the slope we can take points (0,4) and (2,0) thus (y2-y1)÷(x2-x1)

substituting any value of x for either x1 or x2 and any value of y for y1 and y2 we can get

slope is -2

so now we can take either points to find the equation by the formula

y-yo=m (x-xo) where m is slope

after substitution we can get

y-4=-2 (x-0)

y=-2x+4

3 0

2 years ago