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2 years ago

Find the average acceleration of a northbound subway train that slows from 12 m/s to 9.6 m/s in 0.9 s

Physics

1 answer:

o-na [289]2 years ago

6 0

2.7 m/s2 average acceleration of a northbound subway train

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An airplane accelerates from a velocity of 22 m/s to 40 m/s with an acceleration of 2 m/s2. How long does it

andrey2020 [161]

The time it takes the plane to change its velocity is 9s.

Time can be defined the measured or measurable period during which an action, process, or condition exists or continues.

To calculate the time it takes the airplane to change its velocity, we use the formula below.

Formula:

t = (v-u)/a.......... Equation 1

Where:

a = Acceleration
v = Final velocity
u = Initial velocity
t = time

From the question,

v = 40 m/s
u = 22 m/s
a = 2 m/s²

Substitute these values into equation 1

t = (40-22)/2
t = 18/2
t = 9s

Hence, the time it takes the plane to change its velocity is 9s.

Learn more about time here: brainly.com/question/2854969

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1 year ago

The chart shows data for a moving object. A 2-column table with 3 rows. Column 1 is labeled time in seconds with entries 2, 4, 6

Rashid [163]

The object is not accelerating. I think I got this question right

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2 years ago

Katherine johnson’s skill in what field led to nasa’s first moon voyage?

sertanlavr [38]

Answer: Katherine Johnson's knowledge of (mathematics) was instrumental in the return of the Apollo astronauts from the Moon to Earth.

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1 year ago

IF YOUR GOOD AT SCIENCE THEN PLEASE ANSWER THIS ASAP I WILL MARK YOU THE BRAINLIEST

Digiron [165]

Answer:

This is an open circuit

Explanation:

An open circuit I believe

It needs to be closed for the bulb to be turned on

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2 years ago

You want to slide a 0.39 kg book across a table. If the coefficient of kinetic friction is .21, what force is required to move t

uranmaximum [27]

Find the force that would be required in the absence of friction first, then calculate the force of friction and add them together. This is done because the friction force is going to have to be compensated for. We will need that much more force than we otherwise would to achieve the desired acceleration:

$F_{NoFric}=ma=0.39kg \times0.18 \frac{m}{s^2} =0.0702N$

The friction force will be given by the normal force times the coefficient of friction. Here the normal force is just its weight, mg

$F_{Fric}=0.39kg \times 9.8 \frac{m}{s^2} \times 0.21=0.803N$

Now the total force required is:

0.0702N+0.803N=0.873N

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2 years ago