Answer:
Average atomic mass = 17.5 amu.
Explanation:
Given data:
X-17 isotope = atomic mass17.2 amu, abundance:78.99%
X-18isotope = atomic mass 18.1 amu, abundance 10.00%
X-19isotope = atomic mass:19.1 amu, abundance: 11.01%
Average atomic mass of X = ?
Solution:
Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) + (abundance of 3rd isotope × its atomic mass) / 100
Average atomic mass = (78.99×17.2)+(10.00×18.1) +(11.01+ 19.1) /100
Average atomic mass = 1358.628 + 181 +210.291 / 100
Average atomic mass = 1749.919 / 100
Average atomic mass = 17.5 amu.
Answer:
the answer is destructive interference
Answer:
<h2>1200 J</h2>
Explanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
workdone = 60 × 20
We have the final answer as
<h3>1200 J</h3>
Hope this helps you
Answer:
we need to know which atom you're talking about and then you need to say what the mass number is then we can tell how many electrons there are.
(I think)
<span>The answer is A because an elements only consists of one type of atom. Example. the element H (hydrogen) only contains 1 hydrogen atom. I hope this helps!! </span>
