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2 years ago

Which equation could be used to find the length of the hypotenuse?

Mathematics

2 answers:

Allisa [31]2 years ago

5 0

Answer: a^2 + b^2= c^2

Step-by-step explanation:

mihalych1998 [28]2 years ago

4 0

Answer:

y+mx=b

Step-by-step explanation:

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Which ordered pair is a solution to this equation?

ElenaW [278]

For (11, 1): (11 + 3)1 = 14(1) = 14
For (5, 2): (5 + 3)2 = 8(2) = 16 ≠ 14
For (7, 2): (7 + 3)2 = 10(2) = 20 ≠ 14
For (3, 2): (3 + 3)2 = 6(2) = 12 ≠ 14

Therefore, (11, 1) is a solution to this equation.

8 0

2 years ago

Let g(x) be the reflection of f(x) = x 2 + 3 in the x-axis. What is the function rule for g(x)?

nevsk [136]

G(x) will be g(x)=-2x-3 because it is a reflection of f(x) over the x-axis. F(x)'s reflection over the x-axis will become -f(x).

3 0

2 years ago

Read 2 more answers

7 – five-sevenths= A. two-sevenths B. 1two-sevenths C. 6two-sevenths D. 6start fraction 5 over 7 end fraction

Vlada [557]

Answer:

Step-by-step explanation:

To solve it will be easier to turn 7 into a rational number with the same denominator as 5/7

To do this make ratios

$\frac{7}{1}=\frac{x}{7}$

Now solve for x

x = 49

This means that the fraction will be 49/7

$\frac{49}{7}-\frac{5}{7}=\frac{44}{7}$

This can also be written as $6\frac{2}{7}$

4 0

2 years ago

The coordinates of a particle in the metric xy-plane are differentiable functions of time t with:

frez [133]

Answer:

The rate of change of the distance $\frac{ds}{dt}$ when x = 9 and y = 12 is $-7.6\:\frac{m}{s}$ .

Step-by-step explanation:

This is an example of a related rate problem. A related rate problem is a problem in which we know one of the rates of change at a given instant $\frac{dx}{dt}$ and we want to find the other rate $\frac{dy}{dt}$ at that instant.

We know the rate of change of x-coordinate and y-coordinate:

$\frac{dx}{dt}=-2\:\frac{m}{s} \\\\\frac{dy}{dt}=-8\:\frac{m}{s}$

We want to find the rate of change of the distance $\frac{ds}{dt}$ when x = 9 and y = 12.

The distance of a point (x, y) and the origin is calculated by:

$s=\sqrt{x^2+y^2}$

We need to use the concept of implicit differentiation, we differentiate each side of an equation with two variables by treating one of the variables as a function of the other.

If we apply implicit differentiation in the formula of the distance we get

$s=\sqrt{x^2+y^2}\\\\s^2=x^2+y^2\\\\2s\frac{ds}{dt}= 2x\frac{dx}{dt}+2y\frac{dy}{dt}\\\\\frac{ds}{dt}=\frac{1}{s}(x\frac{dx}{dt}+y\frac{dy}{dt})$

Substituting the values we know into the above formula

$s=\sqrt{9^2+12^2}=15$

$\frac{ds}{dt}=\frac{1}{15}(9(-2)+12(-8))\\\\\frac{ds}{dt}=\frac{1}{15}\left(-18-96\right)\\\\\frac{ds}{dt}=\frac{1}{15}(-114)=-\frac{38}{5}=-7.6\:\frac{m}{s}$

The rate of change of the distance $\frac{ds}{dt}$ when x = 9 and y = 12 is $-7.6\:\frac{m}{s}$

7 0

2 years ago

Given this graph, which equation below would give you this graph?

Shalnov [3]

Answer:

Sally has seven times as many dimes as nickels. Their value is $3.00. How many nickels does she have?

4 nickels

7 nickels

28 nickels

Step-by-step explanation:

7 0

2 years ago