Answer:
<h2>
Yes, this is a right triangle.</h2>
Step-by-step explanation:
Hypotenuse always have the highest number than base and perpendicular.
Hypotenuse ( h ) = 15
Base ( b ) = 9
Perpendicular ( p ) = 12
Let's see whether the given triangle is a right triangle or not
Using Pythagoras theorem:
Plugging the values,
Evaluate the power
Calculate the sum
Hypotenuse is equal to the sum of perpendicular and base.
So , we can say that the given lengths of the triangle makes a right triangle.
Hope this helps..
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(1 / 4) = .25
.25 * 100% = 25%
Uncle Bill ate 25%
Cousin Chris ate 15%
.3 * 100% = 30%
Cousin Timmy ate 30%
Little Dave ate 12%
You ate none.
Cousin Timmy ate the most, 18% of the turkey is left, and 82% of the turkey was eaten.
Defend my work in writing:
I converted my fractions and decimals to percents to find the different percents eaten for each person.
Answers:
- Discrete
- Continuous
- Discrete
- Continuous
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Explanations:
- This is discrete because we can't have half a basketball, or any non-whole decimal value to represent the number of basketballs. We can only consider positive whole numbers {1,2,3,4,...}. A discrete set like this has gaps between items. In other words, the midpoint of 2 and 3 (the value 2.5) isn't a valid number of basketballs.
- This is continuous because time values are continuous. We can take any two different markers in time, and find a midpoint between them. For example, the midpoint of 5 minutes and 17 minutes is 11 minutes since (5+17)/2 = 22/2 = 11. Continuous sets like this do not have any gaps between items. We can consider this to be densely packed.
- This is the same as problem 1, so we have another discrete function. You either score a bullseye or you don't. We can't score half a bullseye. The only possible values are {1,2,3,4,...}
- This is similar to problem 2. This function is continuous. Pick any two different positive real numbers to represent the amount of gallons of water. You will always be able to find a midpoint between those values (eg: we can have half a gallon) and such a measurement makes sense.
So in short, always try to ask the question: Can I pick two different values, compute the midpoint, and have that midpoint make sense? If so, then you're dealing with a continuous variable. Otherwise, the data is discrete.
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(2x+3)(2x-3)
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