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The solution to the quadratic equation are option C) x= -5 and option E) x=3.
<u>Step-by-step explanation</u>:
The given quadratic equation is x²+2x-15 = 0.
Using the factorization method,
- product of the roots should be -15.
- Sum of the roots should be 2.
⇒ -15 = 5 -3
⇒ 2 = 5+(-3)
(x+5)(x-3) = 0
Therefore, x = -5 and x = 3
Answer:
XQ = 12
Step-by-step explanation:
In this question it asks for XQ instead of x, but you need to find x first.
1. Find x.
XQ is half of MQ so this statement is true: 3x - 3 = 2(2x - 6)
Solve for x.
3x - 3 = 2(2x - 6)
Distribute 2.
3x - 3 = 4x - 12
Isolate x.
3x = 4x - 9
-x = -9
Divide -1 out.
x = 9
Now solve for XQ, which the equation is given.
XQ = 2(9) - 6
XQ = 18 - 6
XQ = 12
Answer:
Step-by-step explanation:
12+x+10=480
22+x=480
x=458
2(12)+2(x+10)=480
24+2x+20=480
44+2x=480
2x=436
x=218
Answer:
k = 13 The smallest zero or root is x = -10
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Work Shown:
note: you can write "x^2" to mean "x squared"
f(x) = x^2+3x-10
f(x+5) = (x+5)^2+3(x+5)-10 ... replace every x with x+5
f(x+5) = (x^2+10x+25)+3(x+5)-10
f(x+5) = x^2+10x+25+3x+15-10
f(x+5) = x^2+13x+30
Compare this with x^2+kx+30 and we see that k = 13
Factor and solve the equation below
x^2+13x+30 = 0
(x+10)(x+3) = 0
x+10 = 0 or x+3 = 0
x = -10 or x = -3
The smallest zero is x = -10 as its the left-most value on a number line.
Hope this was Right