Answer:
I just learned about this, and if its wrong i am so so sorry
Step-by-step explanation:
a= 120
b= 60
w= 120
x= 120
r= 105
q= 105
p= 105
Answer:
(-8x+7y)(−8x+7y)+(2x-2y)(2x−2y)= simplified - 68x^2+53y^2−120xy
I hope this helps ! <3
Step-by-step explanation:
Answer:
Question 1: Option C, 2x^2(x - 3)(x^2 + 3x + 9)
Question 2: Options 1, 2, 5
Step-by-step explanation:
Question #3
Step 1: Factor
2x^5 − 54x^2
2x^2(x^3 - 27)
<em>2x^2(x - 3)(x^2 + 3x + 9)</em>
<em />
Answer: Option C, 2x^2(x - 3)(x^2 + 3x + 9)
Question #2
p(x) = 4x^6 + 32x^3
<u>Step 1: Factor</u>
4x^6 + 32x^3
4x^3(x^3 + 8)
<em>4x^3(x + 2)(x^2 - 2x + 4)</em>
<em />
Answer: Options 1, 2, 5
<u>Answer:</u>
Amount collected in 2012 = 3.49
and in 2013 = 3.35
<u>Explanation:</u>
Let x be the baggage fees collected in 2013 and
y be the baggage fees collected by airlines in 2012
From the given question we can obtain two equations as follows:
x + y = 6.84 $ - eq 1
and
y = 0.14 + x
as fees in 2012 exceeds that in 2013 by 0.14$
Now, solving these two equations by substitution,
we substitute y = 0.14 + x in eq 1
and solve for x,
which gives us x = 3.35 and
substituting this value in eq 1
we get y = 3.49